I know how to do the magic 21 card trick, the 3 rows of 7 are the important bit, when the person says which row their card is in, gather them into the rows horizontally, one on top of the other so you will have three piles, gather them all together and make sure the pile containing thier card is put in the middle then lay them out again, once again place the pile with their card in the middle, lay them out for a third and final time, do the same again then count out the cards, their card will be the 11th one.
Completely right
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I know how to do the magic 21 card trick, the 3 rows of 7 are the important bit, when the person says which row their card is in, gather them into the rows horizontally, one on top of the other so you will have three piles, gather them all together and make sure the pile containing thier card is put in the middle then lay them out again, once again place the pile with their card in the middle, lay them out for a third and final time, do the same again then count out the cards, their card will be the 11th one.
Completely right
When you lay the cards out I assume you lay them out vertically?
I know how to do the magic 21 card trick, the 3 rows of 7 are the important bit, when the person says which row their card is in, gather them into the rows horizontally, one on top of the other so you will have three piles, gather them all together and make sure the pile containing thier card is put in the middle then lay them out again, once again place the pile with their card in the middle, lay them out for a third and final time, do the same again then count out the cards, their card will be the 11th one.
Completely right
When you lay the cards out I assume you lay them out vertically?
Nah you lay them horizontally
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OK, so while on number games this is a very dull-to-look-at problem but has been known to make A-level maths students cry.
A recurring number is where the decimal part goes on forever eg 1/3 when represented as a decimal = 0.3333333333333333 and the 3's go on and on. That means you'll need a short hand to write it, I'll use an "r". So 0.333r = 1/3.
OK, a quick proof ......
if x = 0.333r
10x = 0.333r x 10
10x = 3.333r
9x = 10x - x
9x = 3.333r - 0.333r
9x = 3
x = 3 / 9
x = 1 / 3
x = 0.333r
So x = 0.333r, tell me something we didn't already know! OK now try
x = 0.999r
10x = 0.999r x 10
10x = 9.999r
9x = 10x - x
9x = 9.999r - 0.999r
9x = 9
x = 9 / 9
x = 1
and I seemed to have proved 1 = 0.999r which it isn't? What gives?
When you lay the cards out I assume you lay them out vertically?
Nah you lay them horizontally
Sorry, I mean lay them horizontally but deal them verticially.
If you collect them horizontally and deal them out horizontally then a card that's, say, the 1st in row 2 will remain the 1st card in row 2 all the time and be the 8th card after 3 goes?
The reason they change is because when you deal the cards you deal them across the rows e.g. the 1st in column 1, then 1st card column 2, then 3rd card in column 3, then 2nd card in column 1 and so on and so
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I think the reason this is confusing is because its arranged slightly differently in real life, so if anyone who's going to Thorpe park wants to see some crap magic tricks i'll be more than happy to show them
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The reason they change is because when you deal the cards you deal them across the rows e.g. the 1st in column 1, then 1st card column 2, then 3rd card in column 3, then 2nd card in column 1 and so on and so
Yep, that's what I meant by dealing vertically rather than horizontally, that works!
: Cheers
